Đăt A=1/2 + 2/2^2 + 3/2^3 + 4/2^4 +..... + 100/2^100 =>2A=1 + 1 3/2^2 + 4/2^3 + .....+ 100/2^99 =>A=1+ 1/2 +1/2^2 +1/2^3 + 1/2^4 + ..... +1/2^99 -100/2^100
đătB=1/2 + 1/2^2 + 1/2^3 + 1/2^4 + ..... + 1/2^99 =>2B=1 +1/2 +1/2^2 +1/2^3 +1/2^4 +..... +1/2^98 =>B=1-1/2^99 Vây A=1 + B-100/2^100 =2-1/2^99-100/2^100<2 (đpcm) p.s: thank Đồng nhiều nhé!!!
|